Conversiones Fundamentales de Unidades: Longitud, Masa, Área y Tiempo

Enviado por Chuletator online y clasificado en Otras materias

Escrito el en español con un tamaño de 4,83 KB

a) 0,45 cm a mts:                                     d) 5 hr a seg
0,45=4,5x10-3 mts                                      5 x 3600= 18000= 4500 seg
100                                                           4       1         4                                                           
b) 250 Km a mts
250x1000= 250,000 mts                            e) 2,5 min a seg
                                                                   2,5x60=150seg
c) 34,23 dm a Km:
34,23=3,423x10-3 Km                                    f) 40 seg a hr
1000                                                               40= 0,011hr
                                                                      3600
d) 23,65 mm a cm                                                    
23,65=2,365 cm                                           g) 3600 seg a hr
10                                                                    3600= 1hr
                                                                        3600
e) 1,973 cm2 a mm2                                                  
1,973x(10)2= 1,973x100= 197,3 mm2                 h) 1 min a seg
                                                                    4
f) 0,5 kg a gr                                                0,25x60=15seg
0x5x1000= 500 gr

g) 0,0056 Km a mts                                2) calcula la diferencia
0,0056x1000= 5,6 mts                            en segundos que hay entre 0,8                                                              y 64min
h) 3 kg a gr: 3 x1000=3000                      0,8 hr a seg         64 min a seg
    4             4      1       4 gr           0,8x3600= 2880seg     64x60=3840seg
                                                                         3840seg=960 seg
i) 3450 dm3 a mts3                                                             2880seg
3450=3450=34,45 mts3
 (10)3 1000                                   3)Calcular los segundos contenidos en
                                                      medio día
j) 0,025 m3 a dm3
0,025x103=0,025x1000=25dm3                1 Dia 24hr 1/2 12hr a seg
                                                             12x36000=
k) 0,028 cm2 a dm2
0,028= 0,028=2,8x10-4 dm2
 (10)2    100                             4) calcular la diferencia en horas entre
                                                  280seg y 45min
Unidades de tiempo                       

1 Día__ 24 hr__60min__60seg         280 seg a hr          45min a hr
                                                   280=0,07hr                 45=0,75hr
                                                   3600                           60
a) 1,5hr a seg
1,5x3600=5400seg                               
b) 340 seg a min
340=5,67 mins
 60
c) 18,34 min a hr
18,34=30,57hr
 60



Entradas relacionadas: